How many positive divisors does the number 2337 have?

Main post link -> https://brilliant.org/assessment/kt/solvable_component/fundamental-theorem-of-arithmetic-prime-factors/2172269/

the number 2337 shown is 2^33^7 (2cube3^7; the cube and 7 is small while another two are big) i tried to do it as 2337 and 2^3 x 3^7 but no luck... use up my two attempts already. only one left so i hope to use this attempt fruitfully. can anyone solved this question tell me what is that 2337 actually? thank you very much

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
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Comments

Please do not post live challenges. Try it yourself, or ask after the set is closed.

Vikram Waradpande - 8 years ago

live problem

A Former Brilliant Member - 8 years ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$