0 0 0^0

Calculus Level 2

0 0 0^0 is often defined as equal to 1 1 since lim x 0 + x x = 1 \displaystyle\lim_{x\to 0^+}x^x=1 .

This led a mathematician to claim that lim x 0 + f ( x ) g ( x ) = 1 \displaystyle\lim_{x\to 0^+}f(x)^{g(x)}=1 for all f ( x ) f(x) and g ( x ) g(x) whenever lim x 0 + f ( x ) = lim x 0 + g ( x ) = 0 \displaystyle\lim_{x\to 0^+}f(x)=\displaystyle\lim_{x\to 0^+}g(x)=0 .

Is this claim true?

No Yes

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1 solution

Nick Turtle
Oct 27, 2017

The mathematician August Ferdinand Möbius made the claim.

However, it is said that a commentator who anonymously signed himself as "S" gave a counterexample when f ( x ) = e 1 / x f(x)=e^{-1/x} and g ( x ) = x g(x)=x .

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