My momentum!

The momentum of a moving bus becomes double whose mass is constant them its kinetic energy will become:

double no change it will stop triple quadriple

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions


therefore, 2P=m(2v) <-- since m is constant


KE = ½m(2v)² = ½m4v² = 2mv²

2mv² / ½mv² = 4


therefore KE becomes 4x larger (quadruples).


so, if p is doubled and mass is constant, only possible change would be in v

v becomesm2v

now, ke is proprtional to v^2

so, the K.E. will quadriple

The person who wrote the question and you spelled quadruple wrong.

aaryan vaishya - 2 years, 7 months ago
Noel Lo
Apr 13, 2015

Momentum is a product of mass and velocity so if mass is constant, velocity has to double. Since kinetic energy is proportional to square of velocity, kinetic energy should multiply by 2 2 = 4 2^2 = \boxed{4} .

0 pending reports


Problem Loading...

Note Loading...

Set Loading...