The momentum of a moving bus becomes double whose mass is constant them its kinetic energy will become:
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
P=mv
therefore, 2P=m(2v) <-- since m is constant
============================================
KE = ½m(2v)² = ½m4v² = 2mv²
2mv² / ½mv² = 4
============================================
therefore KE becomes 4x larger (quadruples).