**
This section requires Javascript.
**

You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.

Good....

Siva Prasad
- 7 years, 2 months ago

OMG

A Former Brilliant Member
- 7 years, 2 months ago

Exactly! ;)

Sheikh Sakib Ishrak Shoumo
- 6 years, 12 months ago

3 Helpful
0 Interesting
0 Brilliant
0 Confused

Hello,

as 1+8+27+......................+1000, it is actually n^(3) for n=[1,10].....

1 = 1x1x1

8 = 2x2x2

27 = 3x3x3

64 = 4x4x4

125 = 5x5x5

216 = 6x6x6

343 = 7x7x7

512 = 8x8x8

729 = 9x9x9

1000 = 10x10x10

Therefore,by adding 1+8+27+64+125+216+343+512+729+1000=3025....

3 Helpful
0 Interesting
0 Brilliant
0 Confused

0 Helpful
0 Interesting
0 Brilliant
0 Confused

0 Helpful
0 Interesting
0 Brilliant
0 Confused

formula for um of cubes is (n(n+1)/2)^2. so ans =3025

0 Helpful
0 Interesting
0 Brilliant
0 Confused

(10
*
11)
*
(10*11)/4=3025

0 Helpful
0 Interesting
0 Brilliant
0 Confused

0 Helpful
0 Interesting
0 Brilliant
0 Confused

1^3 +2^3 +3^3 +.........+n^3 = ((n(n+1)/2))^2 Thus n=10 implies, 10*11/2 * 10 *11/2 = 3025

0 Helpful
0 Interesting
0 Brilliant
0 Confused

0 Helpful
0 Interesting
0 Brilliant
0 Confused

×

Problem Loading...

Note Loading...

Set Loading...

Sum of cubes of n consecutive natural number is given by (n(n+1)/2)^2. Therefore,answer=3025.