1 inch x 1 inch tiles

Each letter in the word " B R I L L I A N T " "BRILLIANT" were written in 1 1 inch by 1 1 inch tiles. These tiles were put in a box. If two tiles are drawn at random without replacement, what is the probability that the two letters are the same letters? The answer is in the form x y \dfrac{x}{y} , where x x and y y are positive co-prime integers.

Find 3 x 321 + 3 y 3 3x^{321}+3y^3 .


The answer is 17499.

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1 solution

There are 9 9 letters in the word "BRILLIANT" .

Two letters, "I" and "L" can be picked twice. So, the number of favorable outcomes is 2 2 .

The total number of ways of picking two letters from the word "BRILLIANT" are

( 9 2 ) \Large{9 \choose 2} = = 9 8 2 \dfrac{9\cdot8}{2} = 36 =36

So the probability that the two letters are the same letters is Number of favorable outcomes ÷ \div Total number of Outcomes

= = 2 36 \dfrac{2}{36}

= 1 18 =\dfrac{1}{18} .

Since 1 1 and 18 18 are co-prime,

x y = 1 18 \dfrac{x}{y}=\dfrac{1}{18} .

x = 1 , y = 18 \implies x=1, y=18 .

3 x 321 + 3 y 3 3x^{321} +3y^3

= 3 1 321 + 3 1 8 3 =3\cdot1^{321}+3\cdot18^3

= 3 1 + 3 5832 =3\cdot1 +3\cdot5832

= 3 + 17496 =3 + 17496

= 17499 =\boxed{17499}

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