23
29
27
25

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Exactly like what I did

Ahmed Obaiedallah
- 6 years ago

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I like your approach .. impressive

Ahmed Obaiedallah
- 6 years ago

BEST APPROACH

Nothin Possible
- 6 years, 11 months ago

nice same approach

Miguel Galang
- 5 years, 5 months ago

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i also do the same process...... hehehe....

Libra Khan
- 6 years, 11 months ago

9 boxes + 1= 10/2 = 5, then 49+1=50/2 =25. that's it!

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9+1 =10, and then 10 divided by 2 equals five. 49+1=50, then 50 divided by 2 = 25

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In the given pattern of 3*3 matrix, position of middle term can be given as 3/2=1.5(round off to 2), i.e; middle term is on (2,2) position in the matrix. Now for the value of that middle term we have n^2+(n-1)^2 where, n=position of middle term

So, for the given pattern of 7*7 matrix position of middle term = 7/2= 3.5(round off to 4 ) hence, value of middle term = n^2+(n-1)^2 = 4^2 + (4-1)^2 = 25

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It should be average of 1st and last number in every case.....it is as simple as that!!

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nice one bro!

Agustin Peñalosa Jr.
- 6 years, 11 months ago

its 7^2 =49 .. the middle one will be 25 .. 5^2..

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Makes no sense!!!

VAIBHAV borale
- 6 years, 10 months ago

Add one to greater number and divide by two... ie. (n+1)/2

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A square board with 49 squares has to be a 7x7 grid (7 squared).

The median (middle) number in 7 is the 4th number. The last number after three rows is 21 (7x3).

This means that the 4th number in the 4th row is 25.

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Well, a unique central square will exist only if dimension is n x n , where n is odd and hence n^2 will be the total no. of squares or the last no. of the board.
To find the central no., we can count all the squares till just before the middle row(i.e. (((n-1)/2)
*
n) and then adding the middle element of the row(i.e. (n+1)/2)....
Mathematically, central no.= (n-1)
*
n/2+(n+1)/2
=(n^2+1)/2
or simply, = (Total no. of squares in the board+1)/2

So in this problem, as total no. of squares is 49, the central no. will be = (49+1)/2 =25 Ans.

Hope it helps

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wow, what i do is just root the number of squares then use the centcr as coordinates

Daniel Progrestian
- 6 years, 12 months ago

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In the First Pattern, there were 9 boxes and the central number will be (9+1)/2=5.

For n boxes, the central Number will be (n+1)/2.

For 49 boxes, central no=(49+1)/2=25