For statements that is correct, type 1. For statements that is incorrect, type 2. For statements that is partially correct, type 3. So the answer is a 10-digit number 1) 3 2 7 − 9 = 0 2) lo g 1 0 × lo g 1 0 0 = lo g 1 0 0 0 3) x 2 − 2 x − 3 = 0 has the factors x = − 1 and x = 3 4) 9 9 9 9 9 9 is divisible by 3 5) Since 1 0 ! has 2 trailing zeros, and 2 0 ! has 4 trailing zeros, 1 0 ! + 2 0 ! has 6 trailing zeros 6) s i n 2 4 6 0 ∘ = s i n 3 0 0 ∘ 7) If f ( x ) = c x + d a x + b , then f − 1 ( x ) = c x − a − d x + b 8) 4 x × 4 x = x 9) lim n → 1 n − 1 n 2 − 1 = 2 10) lo g 1 0 1 0 1 0 1 0 = 2 5 π
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