100 Followers Problem Combinatorics

Find the smallest integer k k with the following property:

Given any real numbers a 1 , a 2 , , a d a_{1}, a_{2} ,\ldots, a_{d} such that a 1 + a 2 + + a d = 100 a_{1}+a_{2}+\cdots +a_{d}=100 and 0 a i 1 0 \le a_{i} \le 1 for i = 1 , 2 , , d i=1,2,\ldots,d it is possible to partition these numbers into k k groups (some of which may be empty) such that the sum of the numbers in each group is at most 1.


The answer is 199.

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