A solid sphere has a charge distributed in its volume with a charge density where and are constants and is distance from center. If electric field at is times stronger than that of at , find .
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1st part: By Gauss's Law: ∮ E ⋅ d A = ε Q
At the point r=R/2: E 1 π ( 2 R ) 2 = ε Q 1
At the point r=R: E 2 π R 2 = ε Q 2
We know that E2=8*E1, dividing the equations we get that: 3 2 Q 1 = Q 2
2nd part (to avoid confusion, density will be "D", and derivatives "d"): D = K r a = d V d Q → ∫ d Q = K ∫ r a d V
V = 3 4 π r 3 → d r d V = 4 π r 2
∫ d Q = K 4 π ∫ r a + 2 d r → Q = a + 3 4 π K r a + 3
3 2 Q 1 = Q 2 → 3 2 a + 3 4 π K 2 a + 3 R a + 3 = a + 3 4 π K R a + 3 → 3 2 = 2 a + 3
Therefore, a = 2
I don't know if my solution is the easiest way of doing it. I think it's not considering this is a level 2 problem and my solution is not so simple. If you have a simpler solution please post it.