10000 followers follow up problem

Algebra Level 5

Assume today is December 1st.

On Jun 1 Calvin had 5000 followers and the amount of followers he had doubled every 6 months. Today, he has 10000.

I began brilliant with one follower on Jun 1 and now I have 500 followers as the amount of followers I had has been multiplied by 500 every 6 months.

Assuming the rates at which we gain followers remains exactly constant, how many days after Dec. 1 will it be before I have as many followers as Calvin? Answer to two decimal places.

Assume:

All months have 30 days

You may use a computer software

Logic does not apply (by this I mean exclude the fact that I probably will never have as many followers as Calvin, base your calculations explicitly off of the information given)

The answer is 97.66.

1 solution

Trevor Arashiro
Nov 22, 2014

Calvin= $10000*2^{\frac{x}{180}}$

Me= $500*500^{\frac{x}{180}}$

Setting these two equal to eachother we get $180\left(\dfrac{\log20}{\log250}\right)$

Wolfram alpha yields 97.66

When I joined Brilliant, I had $0$ followers; and now it's 877. So......?

Satvik Golechha - 6 years, 6 months ago

I was thinking that as well. But I couldn't make a problem off of that because the rate at which I gained followers wouldn't increase as fast as Calvin's rate.

Trevor Arashiro - 6 years, 6 months ago

these are days after calvin had 10000 followers and and you had 500 followers you should mention in the question that how many days from june 1 or Dec 1st. It was not understood by me.

Gautam Sharma - 6 years, 6 months ago

What is 'x' will you specify ?

Kudou Shinichi - 6 years, 5 months ago

the amount of days it takes for me to have as many followers as calvin

Trevor Arashiro - 6 years, 5 months ago

10000 followers follow up problem

The answer is 97.66.

1 solution

0 pending reports