Solve the quadratic equation:

${ 2x }^{ 2 }-10x+35= {x }^{ 2 }+10$

$x=5 \text{ only}$
$x=\pm 5$
$x=- \dfrac { 1 }{ 5} \text{ only}$
$x=-5 \text{ only}$

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$\begin{aligned} 2x ^ { 2 } - 10x + 35 = x ^ { 2 } + 10 \\ x ^ { 2 } - 10x + 25 = 0 \\ ( x - 5 ) ^ { 2 } \\ \therefore x = 5 \end{aligned}$ .