The angle of elevation from a point 118 feet from the base of a tower to the top of the tower is $69.8^\circ$ .

What is the approximate height (in feet) of the tower?

Round the answer to two decimal places.

The answer is 320.71.

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The figure given forms a right-angled triangle.

Applying the formula:-

$\tan \theta$ = $\dfrac{\text{Perpendicular}}{\text{Base}}$

$\tan 69.8° = \dfrac{?}{118}$

$2.717 = \dfrac{?}{118}$

$? = 2.717 × 118 \approx \boxed{320.71}$ metres.