$\large{\begin{array}{cccccccc} &&1 &0 & 1 & 1& 0 & 1&0\\ +&&& 1 & 1 & 0& 0 & 1&1\\ \hline && & & & & & &\\ && & & & & & & \\ && & & & & & & \\ \hline \end{array}}$

Considering the addition of binary numbers above, what is the value of this sum written in the decimal base?

The answer is 141.

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In binary base system, only digits 1 & 0 can be used with the value doubling in the next larger unit. That means, in this case, 1+1 = 10 ( $10_{2}$ = $2_{10}$ ).

Then in the addition above, 1+0 = 1 as in decimal process, but when it's 1+1 = 10, the digit 1 (red) will be added up to the next larger unit, leaving 0 down as shown.

As a result, $1011010_{2}$ + $110011_{2}$ = $10001101_{2}$

Now converting the binary number to decimal one by summation of their unit values, we will get:

$10001101_{2}$ = $2^7$ + $2^3$ + $2^2$ + $2^0$ = 141.