111th Problem 2016
An improvised rocket is launched from the top of a building high. The height reached by the rocket after seconds is given by the function:
What is the distance of the rocket from the ground (in feet) after 3 seconds?
Check out the set: 2016 Problems .
The answer is 180.
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1 solution
In this question, just substitute t = 3 in the given equation.
H ( t ) = ( 4 0 × 3 ) − ( 1 0 × 3 2 ) = ( 1 2 0 − 9 0 ) = 3 0 .
So, the distance from the ground is 1 5 0 + 3 0 = 1 8 0 feet.