Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ I }_{ 1 }$ or (current of ${ R }_{ 1 }$ ) of the circuit.

Part One .

The answer is 1.5.

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All three resistors are in parallel with the same voltage source, which implies they are each at the same potential of 150V. By Ohm's Law, the current I1 is just I1 = 150V / R1 = 150/100 = 1.5A.