Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ I }_{ 2 }$ or (current of ${ R }_{ 2 }$ ) of the circuit.

Part One .

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This is part three of the problem.
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The answer is 0.5.

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Resistance = 300 $\Omega$

Therefore

$V = IR \\ \implies I = \frac{V}{R} \\ \implies I = \frac{150}{300} = \fbox{0.5}$