Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ I }_{ 3 }$ or (current of ${ R }_{ 3 }$ ) of the circuit.

Part One .

This is part four of the problem.

The answer is 0.25.

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Voltage in a parallel circuit is constant and the current across each resistance is given by $\dfrac{V_T}{R}$ .

So, $I_3 = \dfrac{V_T}{R_3}\\ \\ = \dfrac{600}{150}\\ \\ = \color{#3D99F6}{\boxed{0.25 A}}$ .