In the above circuit, ${ R }_{ 1 }=100 \ \Omega$ , ${ R }_{ 2 }=300 \ \Omega$ , ${ R }_{ 3 }=600 \ \Omega$ and ${ V }_{ T }=150 \ V$ , what is the total current $I_T$ of the circuit?

The answer is 2.25.

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The total resistance is ${\left(\dfrac{1}{100} + \dfrac{1}{300} + \dfrac{1}{600}\right)}^{-1} = \dfrac{200}{3}$ .

Now, using Ohm's Law:-

$I = \dfrac{V}{R} = \dfrac{150 × 3}{200} = \color{#3D99F6}{\boxed{2.25 A}}$ .