118th Problem 2016

Given the parallel circuit above with the following values:

R 1 = 100 Ω R 2 = 300 Ω R 3 = 600 Ω V T = 150 V { R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V

Find the P 1 { P }_{ 1 } (Power dissipated in resistor R 1 R_1 ) of the circuit.


Part One .
Check out the set: 2016 Problems .
This is part six of a problem.


The answer is 225.

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1 solution

Tom Engelsman
Jan 19, 2017

The three resistors are in parallel, which means they will each be at the same potential as V T V_T . The required power is just P 1 = ( V T ) 2 R 1 = 15 0 2 100 = 225 P_1 = \frac{(V_T)^2}{R_1} = \frac{150^{2}}{100} = \boxed{225} watts.

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