Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ P }_{ 1 }$ (Power dissipated in resistor $R_1$ ) of the circuit.

The answer is 225.

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The three resistors are in parallel, which means they will each be at the same potential as $V_T$ . The required power is just $P_1 = \frac{(V_T)^2}{R_1} = \frac{150^{2}}{100} = \boxed{225}$ watts.