Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ P }_{ 2 }$ (Power) of the circuit.

The answer is 75.

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P=V^2/R=150×150/300=75