(12) - Outcoming - A problem redone.

Geometry Level 4

ABC \text{ABC} is an obtuse triangle such that

{ 3 BC AB 4 BC = sin 2 A 1 2 cot A 2 = sin A + sin B + sin C cos 2 A + cos 2 B + cos 2 C = p \large \begin{cases} \dfrac{3\text{BC} - \text{AB}}{4\text{BC}} = \sin^2\text{A} \\ \dfrac{1}{2}\cot\dfrac{\text{A}}{2} = \sin\text{A} + \sin\text{B} + \sin\text{C}\\ \cos^2\text{A} + \cos^2\text{B} + \cos^2\text{C} = p \end{cases}

Calculate the value of p p .


The answer is 1.25.

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