Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ P }_{ 3 }$ (Power) of the circuit.

The answer is 37.5.

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As voltage is same across all resistors in parallel connection V=150 Now p3=V^2/R3 Where R3 is 600 So from here we get 37.5watt