Given the parallel circuit above with the following values:

${ R }_{ 1 }=100\Omega \\ \\ { R }_{ 2 }=300\Omega \\ \\ { R }_{ 3 }=600\Omega \\ \\ { V }_{ T }=150V$

Find the ${ P }_{ T }$ (Total Power) of the circuit.

The answer is 337.5.

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$\frac{1}{r}=\frac{1}{100}+\frac{1}{600}+\frac{1}{300}=\frac{200}{3}\\ P = \dfrac{V^2}{r}=\dfrac{150^2}{\frac{200}{3}}=337.5$