123456 is not correct

The a b c d e f \overline{abcdef} is a positive integer with distinct digits greater than 0 and lower than 7. If

  • a b \overline{ab} is divisible by 2,
  • a b c \overline{abc} is divisible by 3,
  • a b c d \overline{abcd} is divisible by 4,
  • a b c d e \overline{abcde} is divisible by 5,
  • a b c d e f \overline{abcdef} is divsible by 6.

How many possible values does a b c d e f \overline{abcdef} have?

3 4 0 1 2

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1 solution

Since b , d , f b, d, f are even numbers ( 2 , 4 , 6 2, 4, 6 ) and e e is 5 5 (because it can't be 0 0 ), a a and c c are 1 1 and 3 3 in some order. 3 a + b + c 3\mid a+b+c , so b b has to be 6 6 . If d = 4 d=4 , then even c = 1 c=1 or c = 3 c=3 , 4 ∤ c d 4\not\mid \overline{cd} , a b c d \overline{abcd} , so d = 2 d=2 . From that there are two possible solutions left, which are both correct:

Solution 1: a b c d e f = 163254 \overline{abcdef}=163254

Solution 2: a b c d e f = 361254 \overline{abcdef}=361254

Isn't there a third one: 123654?

Peter van der Linden - 3 years, 11 months ago

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Next to that: 3 doesn't divide 361, do the 2nd option doesn't fit the requirements.

Peter van der Linden - 3 years, 11 months ago

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Sorry can't edit comments. Firs option doesn't fit either. I think the right numbers are: 123654 and 321654. I had I mistake in first calculation, so 2 is right.

Peter van der Linden - 3 years, 11 months ago

My solutions: 123654, 321654

E Koh - 1 year, 10 months ago

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