150 Followers Problem

Algebra Level 5

{ 2 x 2 y z ( 2 2 + 6 ) = ( y z ) 2 × 2 z 2 + x y ( 3 + 2 ) = ( x + y ) 2 y + z x = x a z y z \large{\begin{cases} 2{ x }^{ 2 }-yz\left( 2-\sqrt{2}+\sqrt { 6 } \right) =\left( y-z \right) ^{ 2 }\times 2 \\ z^{ 2 }+xy(\sqrt { 3 } +2)={ (x+y) }^{ 2 } \\ \frac { y+z }{ x } =\frac { x-az }{ y-z } \end{cases}}

For some positive real numbers x , y , z x, y, z satisfy the system of equations above. For some particular value of a a ( a R + a \in \mathbb{R^{+}} ) and the ratio z y \dfrac{z}{y} ( let's say the ratio be m m ), there exist infinitely many solutions for the above given system in ( x , y , z ) (x,y,z) . Find

1000 a + 1000 m \left\lfloor 1000a \right\rfloor +\left\lceil 1000m \right\rceil


Feel free to report if you believe the question is wrong


The answer is 1768.

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