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2 − x 1 2 sin − 1 x is an odd function, thus, the interval [ − 1 , 1 ] is symmetric about 0. This means the first part of the integral is 0.
Now, since ∣ x ∣ is even, ∫ − 1 1 ∣ x ∣ d x = 2 ∫ 0 1 x d x = 1