1936's Year Problem.
In a brilliant family, a fantastic event occurred in 1936's year. In this year, Tommy's age are the same as last two digits of the year that he born, and, coincidentally, the same occurred with him father's age. In this conditions, in 1936, what would be the sum of the age of Tommy and his father?
The answer is 86.
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1 solution
At first, we don't know the decade nor year, but we can stipulate an century. So, consider that the father borned in 1800's. So, we know that an age are measured by: (Actual year - Year born ). Thus, we have, for the father: ( D= dicker number, U= unit number)
1936 - (1800 + D +U) = D + U
136 = 2D + 2U
68 = D + U
So, the father has 68 years old.
Now, for Tommy:
1936 - (1900 + D + Y) = D + U
36 = 2D + 2U
18 = D + U
So, tommy has 18 years.
Thus, the sum of their age is : 68+18 = 86.