Assume we move to a 2 dimensional world, where the periodic table is based on 3 quantum numbers,

n= 1,2,3,4,.....

m*= -(n-1).. -2,-1 ,0 ,1 ,2, ..(n-1)

s = +0.5 or -0.5

Such that m* plays the combined role of both m and l (3-D quantum numbers)

Assume that in this 2-D world, chemical and physical experience from our world is applicable.

Knowing this, in the 2-D world how does the octet rule and the pseudo-octet rule change?

If the number electrons to complete the new rule and new pseudo-rule are
*
n
*
and
*
m
*
respectively,

What is the value of
*
n
*
+
*
m
*
=

(Based of an IChO question)

The answer is 16.

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In the regular octet rule, we have the s, p, d, and f orbitals. To calculate the number of electrons in each shell, we add up all the electrons in each of the subshells in that shell. For example, for n = 2, we sum the 2 electrons in the s subshell AND the 6 electrons in the p subshell to get a total of 8 electrons.

However, subshells would be absent in the 2D model. Thus, we would NOT be adding anything with subshells. For example, n = 1 would have 2 electrons, n = 2 would have 6 electrons, and n = 3 would have 10 electrons. Since the octet rule is filled by n = 2 and the pseudo octet rule is filled by n = 3, the total number is 16 electrons, which is the answer.