2-D Kinematics

If a body starts from rest at t = 0 t=0 and is moving in 2 D 2-D plane with acceleration a = t 5 e t a=t^{5}e^{-t} then find its velocity at t = t=\infty

none of these 2 2 120 120 24 24 6 6

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1 solution

Shivam Jadhav
Apr 1, 2016

d v d t = t 5 e t \frac{dv}{dt}=t^{5}e^{-t}

d v = t 5 e t d t dv=t^{5}e^{-t}dt

0 v d v = 0 t 5 e t d t \int_0^{v}dv=\int_0^{\infty}t^{5}e^{-t}dt

v = Γ ( 6 ) v=\Gamma(6)

v = 5 ! = 120 v=5!=120

It's a gamma function, right?

Parag Zode - 5 years, 2 months ago

yes , you are right.

Ankit Kumar Jain - 3 years, 12 months ago

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