At Pierre & co, the worker Pierre can craft a guitar in 4 days, while the young Paul can craft a guitar in 8 days.

If they were to work together, how many days will it take for them to craft 6 guitars?

The answer is 16.

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why

Muhammad Awais Awan
- 7 years, 1 month ago

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Follow the ratio method, 1 guitar 4 days (PIERE) , 1 guitar 8 days ( PAUL ) therefore, 6 guitar X days Hence : Sum of Ratio = 6/X 1/4 + 1/8 = 6/x HENCE X = 16 Look at my solution if you dont like Ratios

Syed Baqir
- 5 years, 11 months ago

1/4+1/8=3/8.That means the work done is 8/3. Now multiply this by 6,that is 8/3*6=16

Anuj Shikarkhane
- 6 years, 11 months ago

1/4+1/8=6/x

8x(1/4+1/8=6/x)

2x+x=48

x=16

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$\frac{1}{4}$ + $\frac{1}{8}$ = $\frac{6}{x}$

$\frac{2+1}{8}$ = $\frac{6}{x}$

$\frac{3}{8}$ = $\frac{6}{x}$

$x$ = 16

So, they do it in 16 days.

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grt!

Kartik Kwatra
- 7 years, 1 month ago

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Pierre as A, Paul as B

Work done by A in one day 1/4 Work done by B in one day 1/8

X (1/4+1/8)=6

X(2+1/8) =6

X (3/8) =6

X =6×8/3=16

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gud one bro

Saurav Zuer
- 7 years, 1 month ago

nice one pro

Mohamed Fathy
- 6 years, 8 months ago

Rate at which paul and pierre work are x/4 and x/8 rspectively Let them take y days to prepare 6 guitars while working together

Y(x/4)+Y(x/8)=6x Y(x/4+x/8)=6x Y=16

Amrita Pritam
- 6 years, 11 months ago

PierreGuitars + PaulGuitars = 6

PierreGuitars = PierreDays/4 Paul guitars = PaulDays/8

As the days worked are the same for both, PierreDays and PaulDays they are the same. PierreDays = PaulDays = X

---we substitute in terms of X the first equation---
X/4 + X/8 = 6 => 3X/8 = 6

X = 2*8 = 16

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Together they work on 3/8 guitar in 1 day. So 6 guitars can be done in 1
*
8/3
*
6 days= 16 days.

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2 X ((4+4)//8) where // indicates a parallel process =2*8=16

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paul took 8days for 1 guitar meanwhile pierre prepare 2 guitars on 8days theys gonna prep 3 guitars so.doubling 16 days