2 people for 6 guitars ...

paul took 8days for 1 guitar meanwhile pierre prepare 2 guitars on 8days theys gonna prep 3 guitars so.doubling 16 days

1/4+1/8=6/x

8x(1/4+1/8=6/x)

2x+x=48

x=16

$\frac{1}{4}$ + $\frac{1}{8}$ = $\frac{6}{x}$

$\frac{2+1}{8}$ = $\frac{6}{x}$

$\frac{3}{8}$ = $\frac{6}{x}$

$x$ = 16

So, they do it in 16 days.

Total work done by both in one day 1/4+1/8=3/8 So 1 guitar will be completed in 8/3 days.. So 6 guitars in 8/3*6 = 16

Pierre as A, Paul as B

Work done by A in one day 1/4 Work done by B in one day 1/8

X (1/4+1/8)=6

X(2+1/8) =6

X (3/8) =6

X =6×8/3=16

After 8 days 3 guitars are crafted ( 2 by Pierre & 1 by Paul). So it takes 16 days (8+8=16 days) to craft 6 guitars (3+3=6 guitars)

PierreGuitars + PaulGuitars = 6

PierreGuitars = PierreDays/4 Paul guitars = PaulDays/8

As the days worked are the same for both, PierreDays and PaulDays they are the same. PierreDays = PaulDays = X

---we substitute in terms of X the first equation--- X/4 + X/8 = 6 => 3X/8 = 6
X = 2*8 = 16

Each person has a $productivity$ , which is the speed of making the guitar and shows what part of a guitar is made per day. And so Pall's $productivity$ is $\frac{1}{8}$ and Pierre's is $\frac{1}{4}$ . If we let the needed days be $x$ we set the following equation: $x\bigg(\frac{1}{8} + \frac {1}{4}\bigg)=6$ $x\bigg(\frac{1}{8} + \frac {2}{8}\bigg)=6$ $x\bigg(\frac{3}{8}\bigg)=6$ $x=6×\frac{8}{3}$ $x=16$ And therefore the needed days for the six guitars are $16$ .

Lets make both equivalent to 8 days, let x be No. of guitars made: Piere = 2x while Paul = x IN 8 DAYS hence total guitar in 8 days is 3 so 6 = 2 *3 Same as 8 *2 = 16

Pierre and Paul work together.....as for pierre it takes 4 days to make one guitar i.e in 8 days he'll make 2 guitars meanwhile paul takes 8 days to make one guitar so in these 8 days of work together they'll make 3 guitars. Therefore in 16 days they'll make 6 guitars. Hope it clears your doubts.

For 1 guitar they together will take 1/4 +1/8=3/8 = 8/3 days. For making 6 guitars they will take 8/3*6 = 16 days

Together they work on 3/8 guitar in 1 day. So 6 guitars can be done in 1 8/3 6 days= 16 days.

2 X ((4+4)//8) where // indicates a parallel process =2*8=16

let total work=8 units(l.c.m of work done by pierre and paul) work done by pierre in a day =2units also work done by paul in a day = 1units so total work done by both in a day = 3 units 6 unit work will be done by them in = (8/3)*6=16 days