**
Evaluate
**

$\int _{ -2\pi }^{ 2\pi }{ |\sin { x|dx } }$

**
DETAILS
**

**
|y|
**
is the modulus function.

The answer is 8.

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This definite integral is identical to $4\int_{0}^{\pi} \sin(x) dx = -4\cos(x)|_{0}^{\pi} = \boxed{8}.$