There are 2 consecutive positive integers such that the sum of whose squares is 365. Find the smaller of the 2 numbers. Note: Negative numbers are inadmissible.
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Let the numbers be x , x + 1 .
Then we have x 2 + ( x + 1 ) 2 = 3 6 5
Simplifying we have :
x 2 + x − 1 8 2 = 0
Hence we have ( x + 1 4 ) ( x − 1 3 ) = 0
⇒ x = 1 3 , − 1 4 but since negative numbers are inadmissible hence x = 1 3
Finally we get the smaller number as 1 3