0.31
0.86
0.14
0.69

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Was really easy.

Rhishikesh Dongre
- 7 years ago

Yeah. I just wrote a long-ish solution because I was bored.

Finn Hulse
- 7 years ago

yeah same idea

Muhammad Saleem
- 7 years ago

Found the question in a PSAT book my brother gave me, I was flipping through the questions looking for good questions. Found nothing completely amazing as you can see

Robert Fritz
- 7 years ago

4 Helpful
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Los semicírculos de diámetro 2.

Juan Almenara
- 6 years, 12 months ago

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Area of square = 4

Area of 2 semi circles = 2×1/2×3.14×(1)^2 =3.14

Hence shaded region = Area of square - Area of 2 semi circles

= 4 - 3.14 =0.86

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area of square=4 and area of 2 semicircles =22/7 therefore, area of shaded region=4-22/7=0.86

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(2x2) - (∏) = 4-3.14 = 0.86

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area of sqaure=2
*
2=4, area of circle=pi
*
r2 =3.14 => 4-3.14=.86

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Yes that is my answer too K.KJ.GARG.India

Krishna Garg
- 7 years ago

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Simple area of square of side 2 minus 2* area of semi circle

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*
2= 4 square units
and the area of the semi circle = {pi
*
r^2}/2 = [pi
*
1^2]/2 = pi/2
therefore the are of the two semi circles = [pi/2]
*
2 = pi
therefore the area of the shaded part = 4 - pi = 0.86 (approx.)

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First, let's find the area of the square. This is simply $2^2=4$ . Here's what I do on tests: I make a plan of what I'm going to add and subtract and do whatever with and THEN plug in the actual areas:

$\text{SHADED AREA}=\text{SQUARE}-\text{BOTH SEMICIRCLES}$

Notice how the two semicircles can be added up to make a circle. Since it has the same diameter as the side of the square, it's radius is simply one. Plugging this into the formula for the area of a circle,

$A=\pi r^2$

$A=\pi$

Looking back at our battle plan, now we just substitute, which produces $4-\pi\approx\boxed{0.86}$ .