2 tables and 3 books costs $210, 3 tables and 2 books costs $280. Find the price of 1 table.

5 tables and 5 books cost 210+280=490 dollars,so 2 tables and 2 books cost 196 dollars.Because 3 tables and 2 books cost 280 dollars,a table costs 280-196=84 dollars.

Let $T$ and $B$ be the costs of one table and one book in $, respectively. We have the two equations,

$2T+3B=210$ $\color{#D61F06}(1)$

$3T+2B=280$ $\color{#D61F06}(2)$

Solving $B$ in terms of $T$ in $\color{#D61F06}(1)$ , we get

$2T+3B=210$

$3B=210-2T$

$B=\dfrac{210-2T}{3}$

Now substitute this in $\color{#D61F06}(2)$ , we have

$3T+2\left(\dfrac{210-2T}{3}\right)=280$

Simplifying, we get

$T=\boxed{84}$