cannot be written as
$a{ x }^{ b }+c$
2016
2015
2014

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just take y as x/2. then, we get f(x) = $2{ x }^{ 2 }-\frac { 5 }{ 2 } { x }^{ 2 }+1$ .

So, f(x) = $1-\frac { { x }^{ 2 } }{ 2 }$ .

So, f(2015) = $1-\frac { { 2015 }^{ 2 } }{ 2 }$ .

Hence, a=-0.5, b=2, c=1 and x = 2015.

so 2015+1-2+1=2015.