2=0?

Algebra Level 3

In the proof below, in which step does the first mistake occur?

Step 1. $\ 2 = 1 + 1$
Step 2. $\ 2 = 1 + \sqrt{1}$
Step 3. $\ 2 = 1 + \sqrt{(-1)(-1)}$
Step 4. $\ 2 = 1 + \sqrt{(-1)}$ $\sqrt{(-1)}$
Step 5. $\ 2 = 1 + (i)(i)$
Step 6. $\ 2 = 1 + (-1)$
Step 7. $\ 2 = 0$

Step 3 Step 4 Step 1 Step 7 This proof works as it is Step 2 Step 5 Step 6

0 solutions

No explanations have been posted yet. Check back later!