200 followers problem

If distance between the two points on the fixed smooth inclined plane on which the ball makes first and second collision can be represented as Δ \Delta .

Find Δ \sqrt{\Delta} .


  • Collisions are perfectly elastic. -surface of inclined plane is smooth.
  • No air resistance.
  • h = 25 m , B = 3 0 h=25m,B=30^{\circ}

The answer is 10.

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3 solutions

Jared Jones
May 16, 2015

"Eliminating the parameter of time from the classical expressions of x and y for a body in free fall, H(x)= -(2/150)x^2 +x/sqrt(3), and G(x)= -x/sqrt(3)." Once the point of intersection is found, use it as the distance on the bottom leg of the 30-60-90 right triangle and simply solve for the hypotenuse.

Jared Jones - 6 years ago

Can u please make a clear solution as it is very untidy and many a times difficult to understand.Pls make a clean solution using latex or take photo from a good camera.Don't delete ur solution as u will forfeit ur chance of editing this solution.

Gautam Sharma - 6 years, 2 months ago
Aditya Tiwari
Mar 22, 2015

It's same problem as in hcv. First conserve linear momentum about line of impact, and as the collision is elastic, the speed will remain same but direction will change and ultimately it will be a projectile on incline whose range would come out to be 8 h s i n θ 8hsin\theta where h is the height from which ball is dropped and now substituting the values we get range as 100 and its root as 10 which is the answer.

way too easy

Akash singh - 5 years, 10 months ago

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