#2015_20 Solve for x x

Algebra Level 5

Find the sum of values of x x for which the sixth term from beginning of the expansion of E = ( 3 log 3 9 x 2 + 7 ( 1 5 log 7 ( 4 ) . 3 x 2 9 ) ) 7 E={\large\large \left( { 3 }^{ \log _{ 3 }{ \sqrt { { 9 }^{ \left| x-2 \right| } } } }+{ 7 }^{ \left( \frac { 1 }{ 5 } \log _{ 7 }{ (4).{ 3 }^{ \left| x-2 \right| } } -9 \right) } \right) }^{ 7 } is 567 .

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The answer is 4.

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