What is the mean of all positive divisors of the number 2016?
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2 0 1 6 = 2 5 × 3 2 × 7 No. of divisors= ( 5 + 1 ) ( 2 + 1 ) ( 1 + 1 ) = 3 6
Sum of them= ( 2 0 + 2 1 + 2 2 + 2 3 + 2 4 + 2 5 ) ( 3 0 + 3 1 + 3 2 ) ( 7 0 + 7 1 ) = 6 5 5 2
Hence mean = 3 6 6 5 5 2 = 1 8 2