2016 is absolutely awesome 20

Calculus Level 5

lim n 1 n 2 k = 1 n 1 k 2016 + n k 1 n = ? \large\displaystyle \mathop{\lim}_{n\to\infty} \dfrac{1}{n^2}\sum_{k=1}^{n-1} k\left\lfloor\sqrt{2016}+\dfrac{n-k-1}{n}\right\rfloor =\, ?


This is a part of the Set .


The answer is 22.405.

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