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Let 2 0 1 6 + 2 0 1 5 + 2 0 1 4 − 2 0 1 3 − 2 0 1 2 − 2 0 1 1 = 6 + 5 + 4 − 3 − 2 − 1 = a a = 9 for all those sequences. So finding the number of sequences 2 0 1 6 ÷ 6 = 3 3 6 we can calculate the answer 3 3 6 × a = 3 3 6 × 9 = 3 0 2 4