2018 AMC 12A Problem #3
Probability
Level
2
How many ways can a student schedule 3 mathematics courses—algebra, geometry, and number theory—in a 6-period day if no two mathematics courses can be taken in consecutive periods? (What courses the student takes during the other 3 periods is of no concern here.)
24
18
3
12
6
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Let say we start with three other unconcerned class,we just need to assign the three mathematics class into the gap in between unconcerned class. There are 4 gaps for permutating 3 mathematics class, thus, 4P3=24