2&1

2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 1 = 65535 2 \times 2 \times2 \times2 \times2 \times2 \times2 \times2 \times2\times 2\times 2\times 2\times 2\times 2\times 2\times 2 -1 = 65535

What is its biggest prime factor?

3 15 17 257

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2 solutions

James Pohadi
Mar 30, 2015

2 16 1 2^{16}-1 = ( 2 8 + 1 ) ( 2 8 1 ) =(2^8+1)(2^8-1) = ( 2 8 + 1 ) ( 2 8 1 ) =(2^8+1)(2^{8}-1) = ( 2 8 + 1 ) ( 2 4 + 1 ) ( 2 4 1 ) =(2^8+1)(2^{4}+1)(2^{4}-1) = ( 2 8 + 1 ) ( 2 4 + 1 ) ( 2 2 + 1 ) ( 2 2 1 ) =(2^8+1)(2^{4}+1)(2^{2}+1)(2^{2}-1) = ( 2 8 + 1 ) ( 2 4 + 1 ) ( 2 2 + 1 ) ( 2 + 1 ) ( 2 1 ) =(2^8+1)(2^{4}+1)(2^{2}+1)(2+1)(2-1)

Since ( 2 8 + 1 ) = 257 (2^8+1)=257 is a prime factor, then 257 \boxed{257} is the biggest prime factor.

2^16-1=255 x 257. Since 257 is a prime, then the largest factor must be 257.

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