$211$ is a prime

213=3*71,and these two factors are covered in 211!,which gives 0 as remainder.

Notice that 213 is equal to 3 times 71, which are both factors of 211!. That would mean, that 211! is a multiple of 213, so he remainder is 0.

By Wilson's Theorem ( $(n-1)! \equiv -1 \ \mod(n)$ ) we have:

$212! \equiv 212 \ \mod (213)$

Then $212!/212 \equiv 212/212 \ \mod(213)$

$211! \equiv 0 \ \mod(213)$

213=3*71,and these two factors are there in 211!,