Find the number of consecutive zeroes at the end of 240!.
NOTE - 3000 have 3 zeroes. 301500 consist of two zeroes.
Consecutive zeroes at the end mean the number of 10s as factor.
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divide 240 by 5 find quotient repeat the operations till quotient less than 5
add all quotients will give number of zeroes
240/5 = 48
48/5 = 9
9/5 = 1
48 + 9 + 1 = 58