Find the number of consecutive zeroes at the end of 240!.

NOTE - 3000 have 3 zeroes. 301500 consist of two zeroes.

Consecutive zeroes at the end mean the number of 10s as factor.

The answer is 58.

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divide 240 by 5 find quotient repeat the operations till quotient less than 5

add all quotients will give number of zeroes

240/5 = 48

48/5 = 9

9/5 = 1

48 + 9 + 1 = 58