250 Follower Problem

Algebra Level 5

Let the roots of the equation x m x 2 x 250 m = 0 x^m - x^2 - x - 250m = 0 be ω 1 , m , ω 2 , m , , ω m , m \omega_{1,m}, \omega_{2,m}, \ldots, \omega_{m,m} .

Find the value of

n = 6 250 k = 1 n ω k , n n 2 \sum_{n=6}^{250} \sum_{k=1}^n {\omega^{n-2}_{k,n} }

Inspiration


The answer is 30870.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...