x 3 − 1 2 x 2 + 4 7 x − 6 0 = 0
If a , b , c are roots of the above polynomial. Find the value of ∣ ( a − b ) ( b − c ) ( c − a ) ∣ .
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Could you please tell the formula of discriminant..
b2-4ac is the formula but this is for squre equation...
The above cubic factors into:
x 2 − 1 2 x 2 + 4 7 x − 6 0 = ( x − 3 ) ( x − 4 ) ( x − 5 )
with roots x = 3 , 4 , 5 . Thus, ∣ ( 3 − 4 ) ( 4 − 5 ) ( 5 − 3 ) ∣ = 2 .
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Method I: Without finding the roots, we know that the product we seek is the square root of the discriminant, by definition. The formula for the discriminant gives 4 = 2
Method 2: The roots are easily seen to be 3,4, and 5