250 followers problem

${ 2 }^{ 2015 }\times { 2 }^{ 2014 }\quad =\quad { 2 }^{ 2014 }(2-1)\quad =\quad { 2 }^{ 2014 } =\boxed { \zeta}$

${ 8 }^{ 2015 }\times { 8 }^{ 2014 }\quad =\quad { 8 }^{ 2014 }(8-1)\quad =\quad { 8 }^{ 2014 }\times 7\quad =\quad { 2 }^{ 3\times 2014 }\times 7\quad \\=\quad \boxed {\lambda}$

Thus

$\large {\frac { \lambda }{ { \zeta }^{ 3 } } \quad =\quad \frac { { 2 }^{ 3\times 2014 }\times 7 }{ { 2 }^{ 3\times 2014 } } =\boxed { 7 }}$