2^n - Count_of_factors_of_2((2^n)!) ?

Algebra Level pending

Problem question is problem’s title. {\color{#20A900}\text{Problem question is problem's title.}}

Count_of_factors_of_2 is a function which returns the highest positive integer power of 2 that can be divided evenly (i.e., with a remainder of 0) into its integer argument and otherwise the function returns 0.

n is a non-negative integer and is otherwise not specified.


The answer is 1.

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1 solution

2 n i = 0 n 1 2 i 2^n-\sum _{i=0}^{n-1} 2^i is 1 1 .

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