2nd Math Riddle 2019

Logic Level 1

If

4 2 = 26 8 1 = 79 6 5 = 111 \large {4 \oplus 2=26 \\ 8 \oplus 1=79 \\ 6 \oplus 5=111}

what is 7 3 7 \oplus 3 ?

765 410 265 530

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2 solutions

From the three examples give, we find that the equation is given by a b = a b a + b a \oplus b = \overbrace \square^{a-b} \underbrace \square_{a+b} . Therefore, 7 3 = 4 7 3 10 7 + 3 = 410 7 \oplus 3 = \overbrace 4^{7-3} \underbrace{10}_{7+3} = \boxed{410} .

Rui Chang Lu
Jan 5, 2019

4+2=26 is because 4-2=2 and 4+2=6,so it is 26. Therefore, 7-3=4 and 7+3=10(410).

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