If

$\large {4 \oplus 2=26 \\ 8 \oplus 1=79 \\ 6 \oplus 5=111}$

what is $7 \oplus 3$ ?

765
410
265
530

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From the three examples give, we find that the equation is given by $a \oplus b = \overbrace \square^{a-b} \underbrace \square_{a+b}$ . Therefore, $7 \oplus 3 = \overbrace 4^{7-3} \underbrace{10}_{7+3} = \boxed{410}$ .